
1.Basics
10
Lecture1.1

Lecture1.2

Lecture1.3

Lecture1.4

Lecture1.5

Lecture1.6

Lecture1.7

Lecture1.8

Lecture1.9

Lecture1.10


2.Electrostatics (1)
8
Lecture2.1

Lecture2.2

Lecture2.3

Lecture2.4

Lecture2.5

Lecture2.6

Lecture2.7

Lecture2.8


3.Electrostatics (2)
7
Lecture3.1

Lecture3.2

Lecture3.3

Lecture3.4

Lecture3.5

Lecture3.6

Lecture3.7


4.Current Electricity (1)
9
Lecture4.1

Lecture4.2

Lecture4.3

Lecture4.4

Lecture4.5

Lecture4.6

Lecture4.7

Lecture4.8

Lecture4.9


5.Current Electricity (2)
4
Lecture5.1

Lecture5.2

Lecture5.3

Lecture5.4


6.Capacitor
6
Lecture6.1

Lecture6.2

Lecture6.3

Lecture6.4

Lecture6.5

Lecture6.6


7.RC Circuits
3
Lecture7.1

Lecture7.2

Lecture7.3


8.Magnetism and Moving Charge
16
Lecture8.1

Lecture8.2

Lecture8.3

Lecture8.4

Lecture8.5

Lecture8.6

Lecture8.7

Lecture8.8

Lecture8.9

Lecture8.10

Lecture8.11

Lecture8.12

Lecture8.13

Lecture8.14

Lecture8.15

Lecture8.16


9.Magnetism and Matter
10
Lecture9.1

Lecture9.2

Lecture9.3

Lecture9.4

Lecture9.5

Lecture9.6

Lecture9.7

Lecture9.8

Lecture9.9

Lecture9.10


10.Electromagnetic Induction
14
Lecture10.1

Lecture10.2

Lecture10.3

Lecture10.4

Lecture10.5

Lecture10.6

Lecture10.7

Lecture10.8

Lecture10.9

Lecture10.10

Lecture10.11

Lecture10.12

Lecture10.13

Lecture10.14


11.Alternating Current Circuit
8
Lecture11.1

Lecture11.2

Lecture11.3

Lecture11.4

Lecture11.5

Lecture11.6

Lecture11.7

Lecture11.8


12.Electromagnetic Waves
4
Lecture12.1

Lecture12.2

Lecture12.3

Lecture12.4


13.Photoelectric Effect
5
Lecture13.1

Lecture13.2

Lecture13.3

Lecture13.4

Lecture13.5


14.Ray Optics (Part 1)
12
Lecture14.1

Lecture14.2

Lecture14.3

Lecture14.4

Lecture14.5

Lecture14.6

Lecture14.7

Lecture14.8

Lecture14.9

Lecture14.10

Lecture14.11

Lecture14.12


15.Ray Optics (Part 2)
14
Lecture15.1

Lecture15.2

Lecture15.3

Lecture15.4

Lecture15.5

Lecture15.6

Lecture15.7

Lecture15.8

Lecture15.9

Lecture15.10

Lecture15.11

Lecture15.12

Lecture15.13

Lecture15.14


16.Ray Optics (Part 3)
6
Lecture16.1

Lecture16.2

Lecture16.3

Lecture16.4

Lecture16.5

Lecture16.6


17.Wave Optics
21
Lecture17.1

Lecture17.2

Lecture17.3

Lecture17.4

Lecture17.5

Lecture17.6

Lecture17.7

Lecture17.8

Lecture17.9

Lecture17.10

Lecture17.11

Lecture17.12

Lecture17.13

Lecture17.14

Lecture17.15

Lecture17.16

Lecture17.17

Lecture17.18

Lecture17.19

Lecture17.20

Lecture17.21


18.Atomic Structure
6
Lecture18.1

Lecture18.2

Lecture18.3

Lecture18.4

Lecture18.5

Lecture18.6


19.Nucleus
6
Lecture19.1

Lecture19.2

Lecture19.3

Lecture19.4

Lecture19.5

Lecture19.6


20.XRay
4
Lecture20.1

Lecture20.2

Lecture20.3

Lecture20.4


21.Error and Measurement
9
Lecture21.1

Lecture21.2

Lecture21.3

Lecture21.4

Lecture21.5

Lecture21.6

Lecture21.7

Lecture21.8

Lecture21.9


22.Semiconductors
9
Lecture22.1

Lecture22.2

Lecture22.3

Lecture22.4

Lecture22.5

Lecture22.6

Lecture22.7

Lecture22.8

Lecture22.9


23.Communication Systems
5
Lecture23.1

Lecture23.2

Lecture23.3

Lecture23.4

Lecture23.5

Chapter Notes – Electrostatics (2)
Charge is the property of matter that causes it to produce and experience electrical and magnetic effects. The study of the electrical charges at rest is called electrostatics. When both electrical and magnetic effects are present, the interaction between charges is referred to as electromagnetic.
There exist two types of charges in nature : positive and negative. Like charges repel, and unlike charges attract, each other.
The type of charge on an electron is negative. The charge of a proton is the same as that of an electron but with a positive sign. In an atom, the number of electrons and the number of protons are equal. The atom is, therefore, electrically neutral. If one or more electrons are added to it, it becomes negatively charged and is designated as negative ion. However, if one or more electrons are removed from an atom, it becomes positively charged and is called a positive ion.
The excess or deficiency of electrons in a body gives the concept of charge. If there is an excess of electrons in a body, it is negatively charged. And if there is deficiency of electrons, the body becomes positively charged. Whenever addition or removal of electrons takes places, the body acquires a charge.
The SI Unit of charge is coulomb (C). In SI units, the current is a fundamental quantity, having a unit of ampere (A). The unit of charge is defined in terms of the unit of current. Thus, one coulomb is the charge transferred in one second across the section of a wire carrying a current of one ampere.
As q = It, we have
1 C = (1 A) (1 s)
The dimensions of charge are [A T].
Properties of Charge
(1) Quantization of Charge : Electric charge can have only discrete values, rather than any value. That is, charge is quantized. The smallest discrete value of charge that can exist in nature is the charge on an electron, given as
e = ± 1.6 x 10^{–}^{ 19} C
This is the charge attained by an electron and a proton.
A charge q must be an integral multiple of this basic unit. That is,
Q = ± ne where n = 1, 2, …
Charge on a body can never be (½)e, (^{2}/_{3})e, or 5.7e, etc.
When we rub a glass rod with silk, some electrons are transferred from the rod to the silk. The rod becomes positively charged. The silk becomes negatively charged. The coulomb is a very large amount of charge. A typical charge acquired by a rubbed body is 10 ^{–}^{ 8 }C.
Application 1
A body is having a charge of +0.32 C. How many electrons have been added to or removed from it ?
Solution:
Given q = +0.32 C. Since the charge is positive, there is deficiency of electrons.
n=qe=0.321.6×10−19 = 2 x 10^{18} electrons
Note that the electron itself is not the charge; charge is a property, like mass, of elementary particles, such as the electrons, protons, etc.
(2) Charge is Always Associated with Mass : A charge cannot exist without mass, though a mass can exist without charge. The particles such as photon or neutrino have no (rest) mass. Hence, these particles can never have a charge.
The mass of a body (slightly) increases when it acquires a negative charge (by gaining some electrons). On the other hand, when a body acquires a positive charge (by losing some electrons), its mass (slightly) decreases.
(3) Conservation of Charge : In an isolated system, the total charge remains constant. In other words, charge can neither be created nor destroyed. It can be transferred from one body to the other. Or, equal amounts of positive or negative charges can appear or disappear. This is what happens in pair production and pair annihilation, as shown in figure.
Note that in pair production and pair annihilation, neither mass nor energy is conserved separately, but (mass + energy) is conserved. In pair production energy is converted into mass, while in annihilation mass is converted into energy.
Conservation of charge holds good in all types of reactions.
For example :
Chemical Reaction :
Na^{+ } + Cl^{–}^{ }→ NaCl
Charge : (+e) + (e) = (0)
Radioactive Decay :
n → p + e^{–} + v¯
Neutron proton electron antineutrino
Charge : (0) = (+e) + (e) + (0)
(4) Invariance of Charge : Numerical value of a charge is independent of the frame of reference. It means the value of charge on a body remains the same, whether it is stationary, or moving with a constant velocity or accelerating. In contrast, the mass of a body depends on its speed, and it decreases with increase in speed.
COULOMB’S LAW
The force of interaction of two stationary point charges in vacuum is directly proportional to the product of these charges and inversely proportional to the square of their separation,
F=kq1q2r2
where F is in newton, q_{1} and q_{2} in coulomb, r in metre, and k is a constant given in SI units by
k=14π∈0 = 9 x 10^{9} N m^{2} C^{–}^{2 }
where ∈0 = 8.85 ´ 10^{–}^{12} C^{2} N^{–}^{1} m^{–}^{2} and is called the permittivity of free space (vacuum or air).
For mediums other than air or vacuum, the electrostatic force between two charges becomes
F=14π∈.q1q2r2=14πε0∈r.q1q2r2
Here ∈=∈0∈r, is called the absolute permittivity or permittivity of the medium, and ∈r=∈∈0 is the relative permittivity of the medium which is a dimensionless constant. ∈r is also sometimes called dielectric constant, and is represented by letter K.
The coulomb force acts along the straight line connecting the points of location of the charges.
This force is central and spherically symmetric.
The vector form of Coulomb’s law is F⃗ =kq1q2r2r^. The unit vector has its origin at the source of the force.
For example, to find the force on q_{2}, the origin of r is placed at q_{1} as shown in the figure. If F is the magnitude of the force (a positive scalar), then
F⃗ =+Fr^ means a repulsion
whereas, F⃗ =−Fr^ means an attraction
Analogy with Gravitation Law
Coulomb’s law is analogous to Newton’s law of gravitation :
F=Gm1m2r2
However, following are the important differences :
(a) Electric force between charged particles is much stronger than gravitational force, i.e., F_{E} >> F_{G}_{. }This is why when both F_{E} and F_{G} are present, we neglect F_{G}
(e.g. between two electrons F_{G} = 10^{–}^{39} F_{E}).
(b) Electric force can be attractive or repulsive. But the gravitational force is always attractive.
(c) Electric force depends on the nature of medium between the charges, but gravitational force does not.
Important Points Regarding Coulomb’s Law
(1) Charges are Assumed to be at Rest : When charges are in motion they also produce and experience magnetic forces.
(2) Charges are Assumed to be on Point Particles : Coulomb’s law cannot be directly applied to a finite charge distribution. In such a case (see figure), it is not possible to definitely specify the separation between the charges. However, there is an exception. When the charge is distributed uniformly over a spherical surface, the force on a point charge outside the surface may be computed from Coulomb’s law by treating the charge on the sphere as if it were concentrated at the centre.
Principle of Superposition
The coulomb’s law obeys the principle of superposition. It means that the force between two particles is not affected by the presence of other charges. This principle is used to find the net force exerted on a given charged particle by other charged particles.
The force on a charged particle q_{1} due to point charges q_{2}, q_{3} and q_{4} is the resultant of forces due to individual point charges, i.e.,
F⃗ 1=F⃗ 12+F⃗ 13+F⃗ 14
Note that the notation represents the force on q_{1} due to q_{2}.
How to Solve a Problem using Coulomb’s Law ?
(1) Decide whether the force due to a given charge is attractive or repulsive and show it by drawing vector, pointing towards or away from the given charge, respectively.
(2) Find the magnitude of the force using Coulomb’s law—ignoring the signs of the charges.
(3) Resolve the forces along the given coordinate axes and express them in vector form using i^,j^,k^ unit vector notation, unless otherwise specified.
(4) Use the principle of superposition to find the net force on the charge.
Application 2
Four point charges are located at the corners of a rectangle, as shown in figure. Find the net force acting on the charge q_{1}
Solution:(1) The force F⃗ 12 (between q_{1} and q_{2}) is repulsive, while the forces F⃗ 13 (between q_{1} and q_{3}) and F⃗ 14 (between q_{1} and q_{4}) are attractive.
(2) The magnitude of the forces F⃗ 12, F⃗ 13 and F⃗ 14 are
F12=kq1q2r212=(9×109)(8×10−9)(4×10−9)(3×10−2)2=32×10−5N
F13=kq1q3r213=(9×109)(8×10−9)(8×10−9)(5×10−2)2=23×10−5N
F14=kq1q4r214=(9×109)(8×10−9)(12×10−9)(4×10−2)2=54×10−5N
(3) F⃗ 12 =(−32×10−5)j^
F⃗ 13 =(F13cosθ) i^ + +(F13sinθ) j^
=[−(23)(45)i^+(23)(35)j^]×10−5
=[−18.4i^+13.8j^]×10−5
F⃗ 14 =(−54×10−5) i^
(4) The net force on q_{1} is
F⃗ 1=F⃗ 12+F⃗ 13+F⃗ 14
=[−72.4i^−18.2j^]×10−5N
=[−72.4−18.2]×10−5N
Application 3
Five point charges, each +q are placed on five vertices of a regular hexagon of side L. What is the magnitude of the force on a point charge –q placed at the centre of the hexagon ?
Solution:
Had there been sixth charge +q at the remaining vertex of hexagon, the net force due to all the six charges on –q at O would be zero. The forces due to individual charges will balance each other. That is,
F→R=0
Now if f⃗ is the force due to sixth charge and due to remaining five charges, we must have
F⃗ R=F⃗ +f⃗ =0 i.e., F⃗ =−f⃗
or F=14πε0q×qL2=14πε0[qL]2