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      Class 8 Maths

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      CoursesClass 08MathsClass 8 Maths
      • Cubes and Cube Roots
        6
        • Lecture1.1
          Introduction, Cube, Properties of Cubes and Its Related Sums 38 min
        • Lecture1.2
          Cube Roots, Cube Root of a Cube Number 22 min
        • Lecture1.3
          Cube and its properties related Sum – [Under Construction] 35 min
        • Lecture1.4
          Method of finding Cube Roots – [Under Construction] 21 min
        • Lecture1.5
          Chapter Notes – Cubes and Cube Roots
        • Lecture1.6
          NCERT Solutions – Cubes and Cube Roots Exercise 7.1
      • Exponents and Powers
        10
        • Lecture2.1
          Introduction, Laws of Exponents, Points to be Remember While solving Sums, BODMAS Rule 43 min
        • Lecture2.2
          Sums Related to Laws of Exponents 46 min
        • Lecture2.3
          Sums and Word Problems Related to laws of Exponent, Use of Exponents to Express Small Numbers in Standard Form 54 min
        • Lecture2.4
          Sums Based on Laws of Exponents – [Under Construction] 46 min
        • Lecture2.5
          Words Problems – [Under Construction] 48 min
        • Lecture2.6
          Introduction based Example – [Under Construction] 10 min
        • Lecture2.7
          Problem Based on Fraction Number – [Under Construction] 06 min
        • Lecture2.8
          Represent Smaller Number into exponents – [Under Construction] 09 min
        • Lecture2.9
          Chapter Notes – Exponents and Powers
        • Lecture2.10
          NCERT Solutions – Exponents and Powers Exercise 12.1,12.2
      • Linear Equations in One Variable
        5
        • Lecture3.1
          Introduction, Algebraic Expression, Equations, Solution of linear Equations in One Variable-By Inverse Method, Transposition Method 01 hour 11 min
        • Lecture3.2
          Solving Equation By Cross Multiplication Method, Problems Based on Numbers 56 min
        • Lecture3.3
          Problems Based on Numbers Cont., Geometry, Age, Money Matters 01 hour 05 min
        • Lecture3.4
          Chapter Notes – Linear Equations in One Variable
        • Lecture3.5
          NCERT Solutions – Linear Equations in One Variable Exercise 2.1,2.2,2.3,2.4,2.5,2.6
      • Rational Numbers
        6
        • Lecture4.1
          Introduction of Numbers, Rational Numbers, Properties of Numbers-Closure Property, Commutative Property 01 hour 04 min
        • Lecture4.2
          Commutative Property Cont., Associative Property 52 min
        • Lecture4.3
          Identity-Additive Inverse & Multiplicative Inverse and its Related Sums, Distributivity-Distributivity of Multiplication Over Addition and Subtraction 01 hour 11 min
        • Lecture4.4
          Combined Questions 35 min
        • Lecture4.5
          Chapter Notes – Rational Numbers
        • Lecture4.6
          NCERT Solutions – Rational Numbers Exercise 1.1, 1.2
      • Direct and Inverse Proportions
        4
        • Lecture5.1
          Introduction, Direct Proportion and Inverse Proportion and Its related Sums, Time and Work Related Sums 01 hour 27 min
        • Lecture5.2
          Sums Based On Direct and Inverse Proportion – [Under Construction] 01 hour 30 min
        • Lecture5.3
          Chapter Notes – Direct and Inverse Proportions
        • Lecture5.4
          NCERT Solutions – Direct and Inverse Proportions Exercise 13.1, 13.2
      • Square and Square Roots
        5
        • Lecture6.1
          Introduction and Prime Factorizing Number 01 hour 20 min
        • Lecture6.2
          Shortcut Method: Diagonal Method for Squaring NUmber 05 min
        • Lecture6.3
          Methods for Finding Square Roots 01 hour 06 min
        • Lecture6.4
          Chapter Notes – Square and Square Roots
        • Lecture6.5
          NCERT Solutions – Square and Square Roots Exercise 6.1, 6.2, 6.3, 6.4

        Chapter Notes – Cubes and Cube Roots

        Cube:
        It is a three-dimensional figure made of six equal square sides.

        Cube


        Cube number or Perfect cubes:
        It is a number which is the product of three same numbers.
        Example: Cube number of 2 will be 2 x 2 x 2 = 8. Thus, 8 is a cube number.

        Cubes of some natural numbers:

        Number Cube Number Cube
        1 1 x 1 x 1 = 1 11 11 x 11 x 11 = 1331
        2 2 x 2 x 2 = 8 12 12 x 12 x 12 = 1728
        3 3 x 3 x 3 = 27 13 13 x 13 x 13 = 2197
        4 4 x 4 x 4 = 64 14 14 x 14 x 14 = 2744
        5 5 x 5 x 5 = 125 15 15 x 15 x 15 = 3375
        6 6 x 6 x 6 = 216 16 16 x 16 x 16 = 4096
        7 7 x 7 x 7 = 343 17 17 x 17 x 17 = 4913
        8 8 x 8 x 8 = 512 18 18 x 18 x 18 = 5832
        9 9 x 9 x 9 = 729 19 19 x 19 x 19 = 6859
        10 10 x 10 x 10 = 1000 20 20 x 20 x 20 = 8000
        … … … …


        Properties of Cube Numbers
        :
        1. The cube of an even number will always be an even number.
        Example: 83 = 512, 123 = 1728, etc.

        2. The cube of odd number will always be an odd number.
        Example: 73 = 343, 193 = 6589, etc.

        3. If the cube number have x at its one’s digit or unit’s place then it always end with the digit as shown in the table below:

        Unit’s digit of number Last digit of its cube number Example
        1 1 113 = 1331, 213 = 9261, etc.
        2 8 23 = 8, 123 = 1728, 323 = 32768, etc.
        3 7 133 = 2197, 533 = 148877, etc.
        4 4 243 = 13824, 743 = 405224, etc.
        5 5 153 = 3375, 253 = 15625, etc.
        6 6 63 = 216, 263 = 17576,etc.
        7 3 173 = 4913, 373 = 50653,etc.
        8 2 83 = 512, 183 = 5832, etc.
        9 9 193 = 6859, 393 = 59319, etc.
        10 20 103 = 1000, 203 = 8000, etc.

        Example 1: Find the one’s digit for 27.
        Solution: As the last digit of given number is 7, So the one’s digit for 27’s cube number will be 3.

        Example 2: Find the one’s digit for 149.
        Solution: As the last digit of given number is 9, So the one’s digit for 149’s cube number will be 9.


        Interesting patterns of Cube Number:
        1. Addition of consecutive odd numbers will give Cube Number-
        13         =          1          =          1
        23         =          8          =          3 + 5
        33         =          27        =          7 + 9 + 11
        43         =          64        =          13 + 15 + 17 + 19
        53         =          125      =          21 + 23 + 25 + 27 + 29

        2. Cubes and their prime factors-
        The prime factors of any cube number will be in pair of 3.
        Example:
        (i) 43 = 64 = 2 x 2 x 2 x 2 x 2 x 2 = 23 x 23
        (ii)123 = 1728 = 2 x 2 x 2 x 2 x 2 x 2 x 3 x 3 x 3 = 23 x 23 x 33

        Note:
        (i) If any prime factor is not in pair of 3, then it will not be a perfect cube.
        (ii) Numbers like 1729, 4104, 13832, are known as Hardy – Ramanujan Numbers. They can be expressed as sum of two cubes in two different ways.

        Example 1: Is 128 a perfect cube number?
        Solution: After finding prime factors of 128, we can write 128 = 2 x 2 x 2 x 2 x 2 x 2 x 2
        We can see that each prime factor is not in pair of 3. Hence, 128 is not a perfect cube number.

        Example 2: Find the smallest number by which 675 must be multiplied to obtain a perfect cube.
        Solution: On finding prime factors of 675, we have 675 = 3 x 3 x 3 x 5 x 5.
        We can see that, triplets of 5 is missing. Hence, on multiplying given number by 5 we can have a perfect cube number. Thus, 675 x 5 = 3375 which is a perfect cube number.

        Example 3: Find the smallest number by which 192 must be divided to obtain a perfect cube.
        Solution: On finding prime factors of 192, we have 192 = 2 x 2 x 2 x 2 x 2 x 2 x 3.
        We can see that, triplets of 3 is missing while other numbers have triplets. Hence, on dividing given number by 3 we can have a perfect cube number.
        Thus, 192 / 3 = 64 which is a perfect cube number.


        Cube Roots:
        It is the inverse operation of finding a cube. Symbol ∛ represents a cube-root.
        Example: ∛8 = 2, ∛216 = 6, etc.

        Methods to find a cube root:
        1. Prime factorisation method:
        Follow the steps given below to understand this method:
        Step 1: Find all the prime factors of given cube number.
        Step 2: Make as many group of 3 for all common digit.
        Step 3: Replace group of 3 by respective single digit.
        Step 4: Product of these single digits will give the cube root.

        Example 1
        : Find cube root of 3375.
        Solution:
        Step 1: Find all the prime factors of given cube number.
        The prime factors of 3375 will be 5, 5, 3, 3, 3, 5.
        Step 2: Making group of 3 for every common digit.
        Here, we get (3 x 3 x 3) and (5 x 5 x 5)
        Step 3: Replacing group of 3 by respective digit.
        Thus, we get 3 and 5.
        Step 4: Taking product of digits.
        We get, 3 x 5 = 15.
        Thus, ∛3375 = 15.

        Example 2: Find cube root of 46656.
        Solution: The prime factors of 46656 are 2, 2, 2, 2, 2, 2, 3, 3, 3, 3, 3, 3.
        On grouping, we have 46656 = 2 x 2 x 2 x 2 x 2 x 2 x 3 x 3 x 3 x 3 x 3 x 3.
        So, ∛46656 = 2 x 2 x 3 x 3 = 36.

        2. Estimation Method:
        Follow the steps given below to understand this method:
        Step 1: For given cube number start making groups of three digits starting from the right most digit of the number. We can estimate the cube root of a given cube number through a step by step process.
        Step 2: First group will give you the one’s (or unit’s) digit of the required cube root.
        Step 3: Now take another group, let it be xyz. Find, a3 < xyz < b3. We take the one’s place, of the smaller number a3 as the ten’s place of the required cube root.
        Step 4: The digits obtained in step 2 and step 3 will give the final result.

        Example 1: Find the cube root of 17576.
        Solution:
        Step 1: We will form groups of three starting from the rightmost side of 17567.
        Thus, the two groups formed will be 576 and 17.
        Step 2: For the group 576, the number at unit’s place will be 6.
        Step 3: The other group is 17. The group 17 lies between 23 and 33. Now, as per the method we will take the smaller number which is 2 in this case.
        Step 4: Combining the two digits obtained in step 2 and 3, we get 26.
        Thus, ∛17576 = 26.

        Example 2: Guess the cube root of 4913.
        Solution:The two groups of 4913 will be 4 and 913.
        For group 913, as the last digit is 3 so its cube root will have 7 at its unit place.
        For group 4, it will lie between 13 < 4 < 23. Taking the smaller number which is 1 in this case.
        Thus, ∛4913 = 17.

        Prev Method of finding Cube Roots – [Under Construction]
        Next NCERT Solutions – Cubes and Cube Roots Exercise 7.1

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